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Cron Monitor Never Goes into "Timed Out" State / Stuck In Progress - Testing with time.sleep

getsentry/sentry#103632·44814·Python·222 天未动·9 条评论·上游最近活跃 ·池内状态:可认领
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上游 issue 正文

### How do you use Sentry? Self-hosted/on-premise ### Version 2.44.0 ### Steps to Reproduce In Self Hosted Sentry 24.8.0. We have the following test cron monitor. It works fine for "ok" check-ins and failures, but when adding a time.sleep function in order to test Sentry's "Timed Out" state it never reaches it. It always continues to be in the "In Progress" state. We don't know why. We set runtime in both UI and on client side in config We have some production cron monitors running and experiencing the same thing, they continue to be in progress state rather than in time out state. <img width="1200" height="351" alt="Image" src="https://github.com/user-attachments/assets/dc8b073f-46aa-4b49-97d0-ac15a5ca7ef6" /> <img width="876" height="774" alt="Image" src="https://github.com/user-attachments/assets/1dd19671-a2a0-4d03-bea8-6189582c3ad8" /> ``` import time import sentry_sdk from sentry_sdk.crons import monitor monitor_config = { "schedule": {"type": "crontab", "value": "*/5 * * *"}, "timezone": "America/Chicago", # If an expected check-in doesn't come in `checkin_margin` # minutes, it'll be considered missed "checkin_margin": 1, # The check-in is allowed to run for `max_runtime` minutes # before it's considered failed "max_runtime": 1, # It'll take `failure_issue_threshold` consecutive failed # check-ins to create an issue "failure_issue_threshold": 1, # It'll take `recovery_threshold` OK check-ins to resolve # an issue "recovery_threshold": 1, } @monitor(monitor_slug="test-monitor", monitor_config=monitor_config) def main(): print("Start") time.sleep(10 * 60) print("Finish") if __name__ == "__main__": sentry_sdk.init(debug=True) main() ``` [sentry-debug.log](https://github.com/user-attachments/files/23609635/sentry-debug.log) [sentry-debug_2.log](https://github.com/user-attachments/files/23609639/sentry-debug_2.log) ### Expected Result We see the function to report as "Timed out " when max …
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