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Type Guards and CallBack Parameters are any, if worked, could successfully defined a callback type and respective guard
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上游 issue 正文
**TypeScript Version:** typescript@3.2.0-dev.20181003
Two bugs in one, if both of these issues work, I would be able to properly defined a callback type function call signature overloads and a type guard to go with it.
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CallBack, Type Guards with extends fails, CallBack with overloads signatures types become any type, instead of union of their respective params.
## Issues
1. Callback types params with methods overloading are always any type, should be respective union of each parameters types.
2. Type Guards for more complex type guards doesn't work.
## Summary
If all of this were to work, I would be able to correct write a typescript type for a callback with its associated type guard.
### 1. CallbackTypes are not correctly computed, which expected to be a union of the respective overloads params.
```.ts
// function call signatures.
interface CallBack<T>
{
() : void
(error : Error) : void
(error : undefined, result : T) : void
(error : null, result : T) : void
}
function takeCallBack(callback: CallBack<number>)
{
callback();
callback(null, {A:77});
callback(new Error(''));
}
//Fails to determine which function signature was used to call, because it could have been any of the //formats. The final format is an any type. It would be nice to be able to write a type guard
//[ts] 'result' is declared but its value is never read.
//[ts] Argument of type '(error: any, result: any) => void' is not assignable to parameter of type 'CallBack<number>'
takeCallBack((error, result) => {
});
```
Expected, however, this is not enough information us to write a proper type guards
and we have also lost information about the results, which is the most important.
we need to be able to distinguish between T and T | undefined.
```.ts
takeCallBack((error : Error | undefined | null, result : T | undefined) => {
});
```
## CallBack type formulation
The only was to be…
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