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Private/protected properties on siblings in union types

microsoft/typescript#9974·111137·Go·2754 天未动·3 条评论·上游最近活跃 ·池内状态:可认领
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**TypeScript Version:** 1.8.9 **Code** ``` ts class Example { protected width = 0; constructor(sibling: Example | HTMLCanvasElement) { console.log(sibling.width); } } ``` **Expected behavior:** No errors. **Actual behavior:** Error: `Property 'width' does not exist on type 'Example | HTMLCanvasElement'. Line 4, column 31` The reason this error occurs is that the `width` property is `protected` on `Example` but `public` on `HTMLCanvasElement`. However, the error is confusing for two reasons: 1. The `width` property is available on both component properties in this situation. If the `sibling` parameter had a type of either `Example` or `HTMLCanvasElement`, the code would compile. 2. The error message doesn't explain why the property does not exist on the type. Understanding the error requires the knowledge that properties are only available on union types if they have the same privacy level, even if those properties would be accessible in the component types in the active context. I am not sure if there are situations in which the desired behavior is a compilation error when accessing a potentially protected property on a union type if that property is accessible on all component types. I can't think of any, and so I think the ideal situation would be that the compiler does not throw an error here. However, I think it would be an adequate solution to improve the error message. (I apologize if this has been reported/discussed before. I searched but couldn't find anything exactly along these lines.)
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