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Suggest specifying generic as union if candidates are different
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**TypeScript Version:** 2.6.1.
**Code**
> If a generic type can't be formed by picking one of the inference candidates, you'll get the error you posted.
– https://stackoverflow.com/questions/39905523/why-isnt-the-type-argument-inferred-as-a-union-type/39905723#39905723
This makes sense, however I would like to question whether we can improve the user experience around this, so errors due to this constraint are easier to understand and fix.
For example:
```ts
{
function compare<T>(x: T, y: T): number {
return 1;
}
compare(
'oops',
/* Argument of type '42' is not assignable to parameter of type 'string'. */
42,
);
}
{
function match<T>(cases: { foo: T; bar: T }): T {
return cases.foo;
}
/*
Argument of type '{ foo: number; bar: string; }' is not assignable to parameter of type '{ foo: number; bar: number; }'.
Types of property 'bar' are incompatible.
Type 'string' is not assignable to type 'number'.
*/
match({
foo: 1,
bar: 'foo',
});
}
```
As a TypeScript user, I have struggled with these errors many times, and I've only recently realised the specific constraint on the type system which is the root cause of these errors: generics are picked from the first candidate and are not widened to include all candidates. I have also seen other people struggle with this when learning TypeScript.
We can fix this error by specifying the generic as a union:
``` ts
match<string | number>({
foo: 1,
bar: 'foo',
});
```
However, this fix is really not obvious from the error m…
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