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Suggestion: consolidate generics in union if they match
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**TypeScript Version:** 3.5.2
<!-- Search terms you tried before logging this (so others can find this issue more easily) -->
**Search Terms:** rxjs startWith generics union consolidate same
**Code**
```ts
declare const create: <T>(
t: T,
) => {
startWith: <D>(v1: D) => T | D;
};
// Succeeds
// $ExpectType { foo: number } | { bar: number }
const r1 = create({ foo: 1 }).startWith({ bar: 1 });
// Fails
// $ExpectType { foo: number }
// Actual: { foo: number } | { foo: number }
const r2 = create({ foo: 1 }).startWith({ foo: 1 });
```
Although the expected/actual types are compatible, it's slightly irritating to deal with a union type `T | T` instead of a consolidated type `T`, as it makes type inspection in VS Code much more difficult (especially when the types are large or deeply nested).
Real world use case: https://github.com/ReactiveX/rxjs/issues/4866
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