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`!.` after `?.` should be warned
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上游 issue 正文
This is an anti-pattern on the current type system. And the compiler must not do quick fix so. `!.` after `?.` is simply replaceable with `?.` and should do so.
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For npm: `typescript@next`
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**TypeScript Version:** 3.7.x-dev.20191105
<!-- Search terms you tried before logging this (so others can find this issue more easily) -->
**Search Terms:**
**Code**
```ts
document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // string[]
document.querySelector('_')?.textContent?.split('') ?? 0 // string[] | 0
```
**Expected behavior:**
```ts
document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // unsafe, warning
document.querySelector('_')?.textContent?.split('') ?? 0 // safe
```
**Actual behavior:**
```ts
document.querySelector('_')!.textContent!.split('') // old code
document.querySelector('_')?.textContent!.split('') ?? 0 // unsafe, no warning
document.querySelector('_')?.textContent?.split('') ?? 0 // safe
```
**Playground Link:** <!-- A link to a TypeScript Playground "Share" link which demonstrates this behavior -->
**Related Issues:** <!-- Did you find other bugs that looked similar? -->
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