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Future-proof non-aliasing/always-expanding of mapped/intersection/union/etc. types
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## Search Terms
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non-aliasing types
## Suggestion
<!-- A summary of what you'd like to see added or changed -->
I would like an "officially blessed" way to tell TS if it should give me a type alias, or give me an "expanded" type. (See examples)
Now that this issue has been fixed,
https://github.com/microsoft/TypeScript/issues/32824
the technique I've been using to force TS to not alias a type will break when I migrate to TS 3.6/3.7
## Use Cases
<!--
What do you want to use this for?
What shortcomings exist with current approaches?
-->
In some cases, seeing `Mapped1<T>/Intersected1<T>/Unioned1<T>` is better for a developer (see examples).
In other cases, seeing the full "expanded" type is better (see examples for `Mapped2<T>/Intersected2<T>/Unioned2<T>`)
## Examples
```ts
type Identity<T> = T;
type Mapped1<T> = { [k in keyof T]: [T[k], "mapped"] };
type Mapped2<T> = Identity<{ [k in keyof T]: [T[k], "mapped"] }>;
declare function foo1(): Mapped1<{ x: string, y: number }>;
declare function foo2(): Mapped2<{ x: string, y: number }>;
/*
Aliased, bad
const m1: Mapped1<{
x: string;
y: number;
}>
*/
const m1 = foo1();
/*
Non-aliased, good
const m2: {
x: [string, "mapped"];
y: [number, "mapped"];
}
*/
const m2 = foo2();
//==============================================================
type Intersected1<T> = T & { hi: string };
type Intersected2<T> = Identity<T & { hi: string }>;
declare function bar1(): Intersected1<{ …
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